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Reetika Hooda lost to top seed Aiperi Medet Kyzy of Kyrgyzstan in quarterfinals of women's 76kg event.
Updated : Aug 10, 2024, 04:53 PM IST
Indian wrestler Reetika Hooda displayed remarkable skill and determination as she faced off against top-seeded Aiperi Kyzy of Kyrgyzstan in the quarterfinals of the Women's freestyle 76kg semifinals at the Paris Olympics 2024. Despite a valiant effort, Reetika ultimately fell short against the formidable opponent, with the final score tied at 1-1. Unfortunately, she was defeated via the countback rule.
Prior to this challenging match, Reetika had showcased her prowess by defeating Bernadett Nagy of Hungary in the pre-quarterfinals. The referee halted the contest with just 29 seconds remaining in the second round, as Reetika surged ahead with a commanding 10-point lead, resulting in a final score of 12-2 in her favor.
Reetika Hooda faced defeat against World No. 1, Aiperi Kyzy, in the quarter-final in the women's freestyle 76kg category. Despite the result it was a great effort from her.
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In the first round, the powerful Reetika quickly gained a 4-0 lead by executing an early leg-hold followed by a skillful flip. Although her opponent managed to score a few points, Reetika's dominance continued in the second round with a series of impressive two-pointers.